This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1889 Excerpt: ...by deducting the logarithm of the sum of the two sides from 10. thus 10-0000000 log. 2908 = 3-4635944 6-5364056 Take the triangle (Fig. 175) with b = 580 links, a = 928-6 links, and the angle c = 29 25'. Required the angles A and c. Therefore 75 18' + 45-54' = angle A = 121 12' 75 18'--45-54' = c = 29 24' Rule III.- ...
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This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1889 Excerpt: ...by deducting the logarithm of the sum of the two sides from 10. thus 10-0000000 log. 2908 = 3-4635944 6-5364056 Take the triangle (Fig. 175) with b = 580 links, a = 928-6 links, and the angle c = 29 25'. Required the angles A and c. Therefore 75 18' + 45-54' = angle A = 121 12' 75 18'--45-54' = c = 29 24' Rule III.--From the greatest angle let fall a perpendicular to the base or opposite side, dividing it into two segments, and the whole triangle into two rightangled triangles. Then As the whole base: the sum of the other two sides:: the difference of those sides: the difference of the segment of the base. Then half this difference of segment added to half the base will give the greater segment; and subtracted from half the base will leave the less segment. Given (Fig. 176) Ab = 2200 links. Ac = 1686 Bc = 1272 SOLUTION OF TRIANGLES. Required the segments Ad and D B and the angles. Example. As 2200: 2908:: 864: 481 diff. of segments Half diff. of segs. 240-5 129 adding to and subtracting from base For the Angle A. As A 0 = 1686: radius:: Ad = 1840-5: cos angle A = 85 Therefore angle A = 85 For the Angle B. As B c = 1272: radius:: D B = 860 (practically): cos angle B = 47 27' 9-830011 Therefore angle B = 47 27'. Consequently the angle c is as follows, 180 00'--35 00'-47 27' = 97 88' Thus far I have demonstrated the solution of triangles by means of logarithms, and in conclusion I will give a few illustrations of how it may be done by natural sines, &c. Take the triangle (Fig. 177) whose sides shall be as follows: --Ab = 747-7 links. Bc = 495-45 AO = 560-00 Fig. 177. and opposite this in a table of natural sines will be found the angle 41 80' = angle A. the angle B = 48 80'. Then 180 00' = 90 (c) + 41 80' (a) +...
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Add this copy of Practical Surveying: a Text-Book for Students Preparing to cart. $69.14, good condition, Sold by Bonita rated 4.0 out of 5 stars, ships from Santa Clarita, CA, UNITED STATES, published 2010 by Nabu Press.
Add this copy of Practical Surveying: a Text-Book for Students Preparing to cart. $73.41, good condition, Sold by Bonita rated 4.0 out of 5 stars, ships from Santa Clarita, CA, UNITED STATES, published 2015 by Palala Press.
